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What is the dimensions of a rectangle if the length is 4 centimeters less than twice its width and the perimeter is 34 centimeters what is the dimensions of a rectangle?
you have two equations with two unknowns, length and width let W = width and L = length 2W - 4 = L (1) The perimeter is 2L + 2W 2L + 2W = 34 (2) rearrange (1) and (2) 2W - L = 4 2W +2L = 34 multiply (1) both sides by 2 4W - 2L = 8 2W + 2L =34 add equations 6W = 42 W = 7 solve L from (2) by substituting W = 7 L = 10
What is the sum of 6.210L and 2L expressed in the correct number of significant digits?
8 L
Which is bigger 2l or 2220mL?
2L is Bigger.
Relationship between period and length of a pendulum?
T=1/2l
The perimeter of a rectangle is 26 m The lenght is 1 m more than twice the width find the dimensions?
L = 2w + 1 2l + 2w = 26 2l + l - 1 = 26 l = 9 w = 4
How many cups make up a 2 liter bottle of soda?
1 litre = 1000ml so 2L = 2000ml therefore 2L > 200ml
What is the dimensions of a rectangle if the length is 4 centimeters less than twice its width and the perimeter is 34 centimeters what is the dimensions of a rectangle?
you have two equations with two unknowns, length and width let W = width and L = length 2W - 4 = L (1) The perimeter is 2L + 2W 2L + 2W = 34 (2) rearrange (1) and (2) 2W - L = 4 2W +2L = 34 multiply (1) both sides by 2 4W - 2L = 8 2W + 2L =34 add equations 6W = 42 W = 7 solve L from (2) by substituting W = 7 L = 10
Can 2l over 20 be simplified?
Can 1 and 1/20 be simplified
Rectangular room has width twice of its length When 6 is decreased from both length and width then its area is differed by 108 so find the width?
The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = areaW = 2L from the information in the questionNow we know area, A is equal to length times widthW*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=ANext, we see that when 6 is subtracted from both length and width A becomes 108 less.So (2L-6)*(L-6)=A-108Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.(2L^2-18L+36)=2L^2-108. Now solve for LSubtract 2L^2 from both sides(-18L+36)=(-108)Subtract 36 from both sides(-18L)=(-144)Divide by (-18)L=8We know W=2L so W=16Now lets test our answer.16*8=128(16-6)*(8-6)=10*2=20128-20=108So the answer of L=8 and W=16 is correct.
How do you determine length when given perimeter and width?
Okay. Say, for example if you have a perimeter of 36 inches and your width is 8 inches.Your equation you look like this set up:P = 2L + 2W36 = 2L + 2(8)So,First you would finish multiplying: 36 = 2L + 16Then you would subtract 16 from each side: 36 - 16 = 2L + 16 - 16So it would look like this: 20 = 2LThen you would divide by 2 on each side: 20/2 = 2L/2So your answer would be 10 = L
What is the sum of 6.210L and 2L expressed in the correct number of significant digits?
8 L
What is 2L to cL?
2L = 200cL
What is greater 200ml or 2l?
2L
Which is bigger 2l or 2220mL?
2L is Bigger.
What is the formula for a parallelograms?
P= 2l+2w
How many glasses of water do you drink every day?
1-2l
What fraction of 2l is 20ml?
1%
