you have two equations with two unknowns, length and width
let W = width and L = length
2W - 4 = L (1)
The perimeter is 2L + 2W
2L + 2W = 34 (2)
rearrange (1) and (2)
2W - L = 4
2W +2L = 34
multiply (1) both sides by 2
4W - 2L = 8
2W + 2L =34
add equations
6W = 42
W = 7
solve L from (2) by substituting W = 7
L = 10
The length is (18 centimeters) minus (the width)
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
77cm!
Perimeter of rectangle = (length * 2) + (height * 2 Perimeter = (50.7 * 2) + (40.8 * 2) Perimeter = 183cm
You forgot to put in the length of the rectangle's perimeter.
The length is (18 centimeters) minus (the width)
30 ft
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
150 cm !
46 centimeters
21cm3
77cm!
Perimeter of rectangle = (length * 2) + (height * 2 Perimeter = (50.7 * 2) + (40.8 * 2) Perimeter = 183cm
You forgot to put in the length of the rectangle's perimeter.
The dimensions of this rectangle are that its length is equal to 16 centimeters and its width is equal to 9 centimeters. To find these answers, you need to solve for two unknowns L and W in the equations L- W is equal to 7 and 2 x L plus 2 x W is equal to 50, where L is length and W is width.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?