you have two equations with two unknowns, length and width
let W = width and L = length
2W - 4 = L (1)
The perimeter is 2L + 2W
2L + 2W = 34 (2)
rearrange (1) and (2)
2W - L = 4
2W +2L = 34
multiply (1) both sides by 2
4W - 2L = 8
2W + 2L =34
add equations
6W = 42
W = 7
solve L from (2) by substituting W = 7
L = 10
The length is (18 centimeters) minus (the width)
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
77cm!
Perimeter of rectangle = (length * 2) + (height * 2 Perimeter = (50.7 * 2) + (40.8 * 2) Perimeter = 183cm
You forgot to put in the length of the rectangle's perimeter.
The length is (18 centimeters) minus (the width)
30 ft
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
150 cm !
46 centimeters
21cm3
77cm!
Perimeter of rectangle = (length * 2) + (height * 2 Perimeter = (50.7 * 2) + (40.8 * 2) Perimeter = 183cm
You forgot to put in the length of the rectangle's perimeter.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
9 cm