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What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has one numeral follwed by seven letters followed by one numeral?
This is easiest to answer by working out the probability of not getting such a license plate and subtracting that from 1. There are 10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10 different possible license plates (since there are 10 digits: 0-9 and 26 letters: A-Z). To not have any repeated digits or letters, there are: 10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9 possible license plates (since the two digits must be different and the seven letters must all be different). Meaning the probability of getting one of these is: (10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9)/(10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10) = (25 x 3 x 23 x 11 x 21 x 9)/(26 x 13 x 13 x 13 x 13 x 13) = 3586275/9653618 ⇒ probability of getting at least one repeating digit or number is: 1 - 3586275/9653618 = 6067343/9653618≈ 0.629
What is 23 x 26 x10cm in inches?
23cm x 26cm x 10cm = 5980cm = 2 354.33071 inches
What percentage is 23 out of 31?
26 / 31 x 100 = 74.193548 (or 74.2%)
Solve 2X to the 6Th power Minus128?
(2x6 - 128) 2(x6 - 64) 2(x6 - 26 ) 2 (x3 - 23)(x3 + 23) x=2 ans The answer above is correct to 2(x6-26) 26√(x6-26) 2(x-6√2)3(x+6√2)3 2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3 Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792
How many letter passwords can be formed from ABCs with no repeat?
That depends - on how many letters are in the password - AND - if any letter can be repeated. For example... an eight-digit password has 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 = 208,827,064,576 possible combinations IF every letter can b repeated. If each letter can only be used once, then the formula is 26 x 25 x 24 x 23 x 22 x 21 x 20 x19 = 62,990,928,000 possible combinations.
What is 26 x 24 x 23?
14,352
What is the prime factorization of 192 using exponents?
The prime factorization of 792 is: 2 X 2 X 2 X 3 X 3 X 11.
What is the factor tree for 64?
64 = 8 x 8 = 23 x 23 = 2 x2 x 2 x 2 x 2 x 2 = 26
What is a factor tree for 64?
64 = 8 x 8 = 23 x 23 = 2 x 2 x 2 x 2 x 2 x 2 = 26
What times 5 equals 115?
23 x 5 = 115
What is the product of prime numbers in 26?
Exactly how are they " in " 26 ?Are they the prime numbers smaller than 26 ?1 x 2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 = 223,092,870Are they the prime factors of 26 ?1 x 2 x 13 = 26
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has one numeral follwed by seven letters followed by one numeral?
This is easiest to answer by working out the probability of not getting such a license plate and subtracting that from 1. There are 10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10 different possible license plates (since there are 10 digits: 0-9 and 26 letters: A-Z). To not have any repeated digits or letters, there are: 10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9 possible license plates (since the two digits must be different and the seven letters must all be different). Meaning the probability of getting one of these is: (10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9)/(10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10) = (25 x 3 x 23 x 11 x 21 x 9)/(26 x 13 x 13 x 13 x 13 x 13) = 3586275/9653618 ⇒ probability of getting at least one repeating digit or number is: 1 - 3586275/9653618 = 6067343/9653618≈ 0.629
What is 23 x 26 x10cm in inches?
23cm x 26cm x 10cm = 5980cm = 2 354.33071 inches
What percentage is 23 out of 31?
26 / 31 x 100 = 74.193548 (or 74.2%)
Solve 2X to the 6Th power Minus128?
(2x6 - 128) 2(x6 - 64) 2(x6 - 26 ) 2 (x3 - 23)(x3 + 23) x=2 ans The answer above is correct to 2(x6-26) 26√(x6-26) 2(x-6√2)3(x+6√2)3 2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3 Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792
What are the prime factors for 1472?
The only prime factors of 1472 are 2 and 23, since 1472 = 23 X 26 and 23 itself is prime.
How many letter passwords can be formed from ABCs with no repeat?
That depends - on how many letters are in the password - AND - if any letter can be repeated. For example... an eight-digit password has 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 = 208,827,064,576 possible combinations IF every letter can b repeated. If each letter can only be used once, then the formula is 26 x 25 x 24 x 23 x 22 x 21 x 20 x19 = 62,990,928,000 possible combinations.
