If h = 7 then h squared = 49
1 squared plus 8 squared or 4 squared plus 7 squared
7^2 + 3^2 = 58
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
They are equal. 7 squared is 7 x 7, which equals 49. 6 x 7 = 42, plus another 7 = 49.
(9x2 + 7)(9x2 - 7) = 81x4 - 49
7 Squared is 49. 10 plus 49 is 59.
3 + 43 = 46 7 squared = 49 46 + 49 = 95
x=7
To determine if the given measurements form a right triangle, we can use the Pythagorean theorem. In a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. So, in this case, we would check if (7^2 + 11^2 = 15^2) holds true. Calculating this, we get (49 + 121 = 225), which simplifies to (170 \neq 225). Therefore, the given measurements do not form a right triangle.
6t2+17t+7 = (3t+7)(2t+1) when factored
No, it is not. For a right triangle, from the Pythagoraen theorem, 7 squared plus 9 squared does not equal 12 squared