The rule:
Un = 570n3 - 3280n2 + 5870n - 3155 implies U6 = 37105
-6 - (-5) + 2 - 1 = -6 + 5 + 2 - 1 = -1 + 2 -1 = 1 - 1 = 0
The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
6 * [5-(2-1)] = 6*[5-1] = 6*4 = 24
1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P
6*6=36 1&1; 1&2; 1&3; 1&4; 1&5; 1&6 2&1; 2&2; 2&3; 2&4; 2&5; 2&6 3&1; 3&2; 3&3; 3&4; 3&5; 3&6 4&1; 4&2; 4&3; 4&4; 4&5; 4&6 5&1; 5&2; 5&3; 5&4; 5&5; 5&6 6&1; 6&2; 6&3; 6&4; 6&5; 6&6 For adding up roll one and roll two, the outcomes are 1+1= 2 1+2=2+1= 3 1+3=2+2=3+1= 4 1+4=2+3=3+2=4+1= 5 1+5=2+4=3+3=4+2=5+1= 6 1+6=2+5=3+4=4+3=5+2=6+1= 7 2+6=3+5=4+4=5+3=6+2= 8 3+6=4+5=5+4=6+3= 9 4+6=5+5=6+4= 10 5+6=6+5= 11 6+6= 12 Odds of adding up to those possible outcomes. 2 = 1:36 3 = 2:36 = 1:18 4 = 3:36 = 1:12 5 = 4:36 = 1:9 6 = 5:36 7 = 6:36 = 1:6 You will total seven more times than others. 8 = 5:36 9 = 4:36 = 1:9 10= 3:36 = 1:12 11= 2:36 = 1:18 12= 1:36
It is: 2 and 2/6 minus 1 and 5/6 = 1/2
1/2 x 5/6 is 5/12
1*1=1 1+2=3 3-1=2 2*2=4 4+2=6 6-1=5 5*5=25 25+2=27 answer is 27
1/2 x + 6 = 11 1/2 x + 6 - 6 = 11 - 6 1/2 x = 5 2*(1/2 x) = 5*2 x = 10 1/2 of 10 is 5, 5 plus 6 is 11 QED
It depends on what you define as an outcome. Let me take a simpler case: just two dice.1. Outcomes of possible sums of the two dice:2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 122. Outcomes of possible sets of two dice:{1, 1}, {1, 2}, {1, 3}, {1, 4}, {1, 5}, {1, 6}, {2, 2}, {2, 3}, {2, 4}, {2, 5}, {2, 6}, {3, 3}, {3, 4}, {3, 5}, {3, 6}, {4, 4}, {4, 5}, {4, 6}, {5, 5}, {5, 6}, {6, 6}3. Outcomes of possible combinations of two dice:(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)We would need to know which you need. Assuming you want all the possible combinations of ten 6-sided dice, then it is 610, or 60,466,176.
5: 1 and 5 6: 1, 2, 3 and 6
3 1/2=3 3/6=2 6/6+1 5/6=1 1/6 is the final answer - 1 5/6=1 5/6