It depends on what you define as an outcome. Let me take a simpler case: just two dice.
1. Outcomes of possible sums of the two dice:
2. Outcomes of possible sets of two dice:
3. Outcomes of possible combinations of two dice:
We would need to know which you need. Assuming you want all the possible combinations of ten 6-sided dice, then it is 610, or 60,466,176.
You can get 2, 4, 6, 8, 10, and 12, six even sums all together.
It is 10/36 = 5/18
Outcomes from rolling two dice: Total Probability 2 1/36 3 2/36 4 3/36 5 4/36 6 5/36 7 6/36 8 5/36 9 4/36 10 3/36 11 2/36 12 1/36 So, the probability of rolling 9 or greater is 4/36+3/36+2/36+1/36 = 10/36 ~= 0.278 = 27.8%
The probability is 0.2503
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
If the numbers (or symbols) are all different then 10 outcomes.
You multiply the possibilities so 6 possibilities of the dice and the 10 possibilities of the spinner so in total there are 60 possible outcomes for this situation.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
There are 104, or 10000 permutations of four 10 sided dice.
Well there is 36 different possibilities with rolling 2 6 sided dice. The probability of rolling the sum of 10 with 2 die is 4/36 or 1/8 chance.
The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%
There are 36 possible outcomes when two dice are rolled. The composite outcomes and the number of corresponding events are: 4 - 3 6 - 5 8 - 5 9 - 4 10 - 3 12 - 1 So there are 21 outcomes out of 36 where the result is a composite. So probability of a composite = 21/36 = 7/12 = 0.58333 or 58.333... %
It is 0.0833... recurring.
There are 36 different outcomes when rolling two dice. 4 combinations make 9. 3 make 10, 2 make 11 and 1 makes 12. 4+3+2+1 = 10 10 out of 36 = 10/36 = 0.277777 = 27.8 %
There are 36 different combinations when rolling two dice, of these, there is a 10/36 = 5/18 (27.78%) chance of rolling combined total of 9 or more, or a 6/36 = 1/6 (16.67%) chance of rolling a combined total of 10 or more
Three.