It depends on what you define as an outcome. Let me take a simpler case: just two dice.
1. Outcomes of possible sums of the two dice:
2. Outcomes of possible sets of two dice:
3. Outcomes of possible combinations of two dice:
We would need to know which you need. Assuming you want all the possible combinations of ten 6-sided dice, then it is 610, or 60,466,176.
You can get 2, 4, 6, 8, 10, and 12, six even sums all together.
It is 10/36 = 5/18
Outcomes from rolling two dice: Total Probability 2 1/36 3 2/36 4 3/36 5 4/36 6 5/36 7 6/36 8 5/36 9 4/36 10 3/36 11 2/36 12 1/36 So, the probability of rolling 9 or greater is 4/36+3/36+2/36+1/36 = 10/36 ~= 0.278 = 27.8%
The probability is 0.2503
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
If the numbers (or symbols) are all different then 10 outcomes.
You multiply the possibilities so 6 possibilities of the dice and the 10 possibilities of the spinner so in total there are 60 possible outcomes for this situation.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
There are 104, or 10000 permutations of four 10 sided dice.
There are 36 possible outcomes when two dice are rolled. The composite outcomes and the number of corresponding events are: 4 - 3 6 - 5 8 - 5 9 - 4 10 - 3 12 - 1 So there are 21 outcomes out of 36 where the result is a composite. So probability of a composite = 21/36 = 7/12 = 0.58333 or 58.333... %
Well there is 36 different possibilities with rolling 2 6 sided dice. The probability of rolling the sum of 10 with 2 die is 4/36 or 1/8 chance.
The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%
It is 0.0833... recurring.
There are 36 different outcomes when rolling two dice. 4 combinations make 9. 3 make 10, 2 make 11 and 1 makes 12. 4+3+2+1 = 10 10 out of 36 = 10/36 = 0.277777 = 27.8 %
There are 36 different combinations when rolling two dice, of these, there is a 10/36 = 5/18 (27.78%) chance of rolling combined total of 9 or more, or a 6/36 = 1/6 (16.67%) chance of rolling a combined total of 10 or more
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.