Twice Half as strong. Really? What the heck kind of question is this?
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
Because the environment is Isotonic (having the same or equal osmotic pressure).
Set up. .70(2 gal) + X = .90(X + 2 gal) distribute 1.4 + X = .90X + 1.8 X = .90X + .4 .1X = .4 X = 4
add 4 parts water per part solution
4 ounces
hypotonic
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
You will need more data about all densities (in kg/Litre)and you must be sure of using mass% = (g solute)/(100 g solution)Solve two equations for both X and Y:4*d50*50 = X*d20*20 + Y*d70*70 (based on salt mass balance in diff. sol'n.)4*d50 = X*d20 + Y*d70 (based on solutions mass balance)In which:dm = density of the 'm'% salt solution in kg/Litre)X and Y = volume of the 20% and 70% salt solutions respectively
Beggars and Choosers - 1999 Fifty Three Percent Solution 2-2 was released on: USA: 4 July 2000
Examples are:1- Cold drink 2- Air 3- Milk 4- blood 5- Sugar solution
Because the environment is Isotonic (having the same or equal osmotic pressure).
1. Grinding of the rock salt. 2. Dissolving of the rock salt in water. 3. Filtering of the solution. 4. Repeated processes of crystallization/recrystallization.
4 percent
chemicals (45 percent), road de-icing/ice control salt (31 percent), salt sold to distributors (8 percent), industrial uses (8 percent), agricultural salt (6 percent), food (including table salt, 4 percent)
Set up. .70(2 gal) + X = .90(X + 2 gal) distribute 1.4 + X = .90X + 1.8 X = .90X + .4 .1X = .4 X = 4
add 4 parts water per part solution
4 ounces