A. 16 of 18 percent and 2 of 9 percent
b. 14 of 18 percent and 4 of 9 percent
c. 16 of 9 percent and 2 of 18 percent
d. 14 of 9 percent and 4 of 18 percent
4.84
50 Liters of the 60% solution.
80 liters
50liters
50
4.84
50 liters
256 liters
50 Liters of the 60% solution.
3.0 kg
(x L)((12%) = (100 L)(2%)x = 16.7 liters
80 liters
Depending on the desired concentration of the solution !
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
144liters
I suppose that this solution doesn't exist.