by Special:ContributionsSince there is a zero in the number sentence , the rule of 0 is Everything x 0 is 0.
by Taylor10119 it's not zero because 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 1 x 9 x 0 is 162 so the answer would be 162!!!!
The answer is 0 because no matter what numbers you times together, you will eventually come to the 0 and then the answer is 0.
Example:
2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 1 x 9=4608
Then 4608 x 0=0.
There are infinitely many points that do not lie on the line x + 2y = 9, some of which are (0, 0), (1, 1), (2, 2), (1, 2), (2, 1), (500, 122342), (12122, 567). To decide if a given point lies on the line put the values for its x and y coordinates into the equation and see if it they equal 9: for points: (0, 0): x + 2y = 0 + 2 × 0 = 0 ≠ 9 → (0, 0) is not on the line (1,0) : x + 2y = 1 + 2 × 0 = 1 ≠ 9 → (1, 0) is not on the line (1, 2) : x + 2y = 1 + 2 × 2 = 5 ≠ 9 → (1, 2) is not on the line (1, 4) : x + 2y = 1 + 2 × 4 = 9 = 9 → (1, 4) is on the line If you had a set of points given to you from which you had to select the one not on the line, you'll need to test each one separately, as above, to find which one does not work.
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
2(x+5) =3X+1 => 2x+10-3x-1=0. => -x+9 => x=9
9x2 + 7x = 2 9x2 + 7x - 2 = 0 9x2 + 9x - 2x - 2 = 0 9x(x + 1) - 2(x + 1) = 0 (9x - 2)(x + 1) = 0 x ∈ {-1, 2/9}
2x2 = x+1 => 2x2-x-1= 0 Divide all terms by 2: x2-1/2x-1/2 = 0 Completing the square: (x-1/4)2-1/2 = 0 (x-1/4)2-1/2-1/16 = 0 (x-1/4)2-9/16 = 0 (x-1/4)2 = 9/16 Square root both sides: x-1/4 = -/+ 3/4 x = 1/4 -/+ 3/4 x = -1/2 and x = 1
There are infinitely many points that do not lie on the line x + 2y = 9, some of which are (0, 0), (1, 1), (2, 2), (1, 2), (2, 1), (500, 122342), (12122, 567). To decide if a given point lies on the line put the values for its x and y coordinates into the equation and see if it they equal 9: for points: (0, 0): x + 2y = 0 + 2 × 0 = 0 ≠ 9 → (0, 0) is not on the line (1,0) : x + 2y = 1 + 2 × 0 = 1 ≠ 9 → (1, 0) is not on the line (1, 2) : x + 2y = 1 + 2 × 2 = 5 ≠ 9 → (1, 2) is not on the line (1, 4) : x + 2y = 1 + 2 × 4 = 9 = 9 → (1, 4) is on the line If you had a set of points given to you from which you had to select the one not on the line, you'll need to test each one separately, as above, to find which one does not work.
x+9=xx x+9=x^2 x^2-x-9=0 Quadratic formula: x=[1±√(1+36)]/2 x=(1±√37)/2
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
2(x+5) =3X+1 => 2x+10-3x-1=0. => -x+9 => x=9
9x2 + 7x = 2 9x2 + 7x - 2 = 0 9x2 + 9x - 2x - 2 = 0 9x(x + 1) - 2(x + 1) = 0 (9x - 2)(x + 1) = 0 x ∈ {-1, 2/9}
f(2) = 8 - 26 + 18 = 0 (x-2) is a factor of f(x), x = 2 f(x) = (x-2)(x2 + 2x -9) x2 + 2x - 9 = 0 (x+1)2 - 10 = 0 x + 1 = +-sqrt10 x = -1 + sqrt10, -1 - sqrt10, 2
2x2 = x+1 => 2x2-x-1= 0 Divide all terms by 2: x2-1/2x-1/2 = 0 Completing the square: (x-1/4)2-1/2 = 0 (x-1/4)2-1/2-1/16 = 0 (x-1/4)2-9/16 = 0 (x-1/4)2 = 9/16 Square root both sides: x-1/4 = -/+ 3/4 x = 1/4 -/+ 3/4 x = -1/2 and x = 1
243,090 = (2 x 100000) + (4 x 10000) + (3 x 1000) + (0 x 100) + (9 x 10) + (0 x 1) OR (2 x 10^5) + (4 x 10^4) + (3 x 10^3) + (0 x 10^2) + (9 x 10^1) + (0 x 10^0)
0, 9, 18, 27, etc.; just add 9 at a time to get more multiples. Or multiply 9 by any integer: 9 x 0 = 0 9 x 1 = 9 9 x 2 = 18 9 x -1 = -9 etc.
9,200,105 = (9 x 1000000) + (2 x 100000) + (0 x 10000) + (0 x 1000) + (1 x 100) + (0 x 10) + (5 x 1)
-1