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3x2 + 2x + 2 = 0
Can not be factored. You can however solve it for x:
3x2 + 2x = -2
x2 + 2x/3 = -2/3
x2 + 2x/3 + 1/9 = -2/3 + 1/9
(x + 1/9)2 = -5/9
x + 1/9 = ±√(-5/9)
x = -1/9 ± i√(5/9)
x = -1/9 ± i√5 / 3
x = -1/9 ± 3i√5 / 9
x = (-1 ± 3i√5) / 9
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What are the 2 solutions for x if 3x2 plus 2x-8 equals 0?
3x2+2x-8=0 Delta = 22-4*3*-8= 100 So x = (-2 + sqrt(100))/(2*3) or x = (-2 - sqrt(100))/(2*3) x = 4/3 or x=-2
4x2 plus 2x equals?
Assuming that 4x2+2x = 0: 2x (2x+1) = 0 2x = 0 or 2x+1 = 0 x = 0 or -1/2
When factored what is the solution set 3x squared minus 19x minus 14 equals 0?
3x2 - 19x - 14 = 0 3x2 - 21x + 2x - 14 = 0 3x(x - 7) + 2(x - 7) = 0 (x - 7)(3x + 2) = 0 x - 7 = 0 or 3x + 2 = 0 x = 7 or x = -2/3
Which is the solution set for 3x2 - 4x - 15 equals 0?
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
What is 2x plus 8y plus 7 equals 0?
2x = -7 - 8y
What is 3x squared plus 2x minus 8 equals 0?
3x2 + 2x - 8 = 0 is a quadratic equation.
How do you solve 3x squared plus 2x equals 16?
3x2 + 2x = 16 ∴ 3x2 + 2x - 16 = 0 ∴ 3x2 - 6x + 8x - 16 = 0 ∴ 3x(x - 2) + 8(x - 2) = 0 ∴ (3x + 8)(x - 2) = 0 ∴ x ∈ {-8/3, 2}
How do you factor 3x3-3x2-48x-60 equals 0?
3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
How do you factor 5x cubed minus 3x squared plus 2x equals 0?
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
X2 plus 8x equals -3x2 plus 5?
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
Factor 2x squared - 6x plus 4 equals 0?
(2x-4)(x-1) = 0
How do you factor x squared -2x-3 equals 0?
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
Put the equation in the form ax2 plus bx plus c equals 0 x2-3 equals 3x2 plus 8x?
2x^2 + 8x + 3 = 0
What is 3x squared minus 2x minus 5 equals 0?
3x2 - 2x - 5 = (3x - 5)(x + 1) = 0 gives a solution of x = 5/3 or -1. Was that what you wanted?
How do you factor 4x2 plus 12x plus 9 equals 0?
(2x + 3)(2x + 3)
How do you factor 6x - 6x -16?
6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
How do you factor 6x squared plus 3x equals 0?
3x(2x + 1)
