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Zero

The cast of 2x0 - 2013 includes: Marta Flich as Lola

I'm assuming the equation is 10 - 2x = 0? If that's the case, the answer is 5 (not -5)

The answer is 2. 2x = 2x1 So you follow the usual rule about bring down the exponent and subtract one from it and you get 1*2x0= 2x0=2

2x0+300 = 900 Solving the equation: 2x0 = 600 So the measures of the angles are: 90 degrees, 60 degrees and 30 degrees.

no just write zero. or maybe like an example 2x0=0

It's more of an arithmetic expression, however, 2x0 + 3x0 = y would be algebraic.

2+2+2+2+2+2+2+2+2+2+2+2+(2x0) =2+2+2+2+2+2+2+2+2+2+2+2+0 =24

It is odd. The definition of an odd number is "a number a is odd if there exists an integer n such that a = 2n + 1." Let a = 1 and let n = 0, so 1 = (2x0) + 1.

Marta Flich has: Performed in "Impares" in 2008. Performed in "Impares premium" in 2010. Played herself in "Jumping" in 2011. Played Lola in "2x0" in 2013. Performed in "Sinestesia" in 2014.

most commonly you would place the highest exponent first. x0 = 1. 54x3 + 62x2 - 344x + 2 = 0

(4x1)+(2x0)+(1x1)=5. The first number is the place value. The second number is if there's a zero or a 1. Notice that the first number is half of the last first :) (last first) number. 1001=9. 1101=13. Who can do 10001101?

double the number of itself , but when it is 1 or 0 , for 1 , you get 1 , for 0 you get 0 . Meaning for example , 1 . 1x1=1 2x1=2 3x1=3 4x1=4 The 2nd example would be , 1x0=0 2x0=0 3x0=0 4x0=0

For a quadratic function, there is one minimum/maximum (the proof requires calculus) and also it is either always convex or concave (prove is also calculus) it is continuous every where, hence, it can have a maximum of 2 roots. Graph it. If there is more than 2 roots, by Intermediate Value Theorem, it cannot be convex/concave everywhere. It will HAVE to have two intervals of increasing or decreasing. It can be easily proven that given any quadratic function f(x), if x = x0 is a minimum/maximum, and x=a != x0 is a root, then 2x0-a is also a root. It is still true that a = x0 as 2x0-x0=x0 implying it is the only root. But the concept of min/max requires Calculus to prove existence. So, this is Calculus, not algebra.

74 is not divisible by 4; but704 is divisible by 4.74: 2x7+ 4 = 18; 2x1 + 8 = 10; 2x1 + 0 = 2 which is not 4 nor 8, so 74 is NOT divisible by 4704: 2x0 + 4 = 4 which is 4 or 8, so 704 IS divisible by 4

A line intercepts the y axis when x=0. If we put x=0 into the equation we get 2x0 + 6y = 36 6y = 36 y = 6 (dividing both sides by 6) Thus the line intercepts the y axis when x is 0 and y is 6. This is the point with the coordinates (0,6)

Odd numbers are defined as numbers of the form 2n+1 for some integer n. Since 0 is an integer, 2x0+1=1 is an odd number. Another way to think of it is that an odd number is one that is not even. An even number is one of the form 2n for some integer n. 1 is not even so it is odd. This means 0 is even, by the way.

Including zero, the first three common multiples are 0, 8, and 16. Not including zero, the first three would be 8, 16, and 24. These numbers represent integer multiples of 8, because 8 is already a multiple of 2. 0 = 8x0 = 2x0 8 = 8x1 = 2x4 16 = 8x2 = 2x8 24 = 8x3 = 2x12

The answer is -13 1/3ohere is the detailed calculation for the problem:Let x0 be the angle, then;(180 - x0) - 2[180 - (90 - x0)] =40(180 -x0) - 2[90+x0]=40180 -x0 - 180 - 2x0=40-3x0=40hencex0= -13 1/3oAny comments are welcome

2x-y=14, x=0 First, substitute 0 in place of x. (2x0)-y=14 Multiply 2 times 0. 0-y=14 That gives you... -y=14 Because we are solving for y, and y must be positive, divide each side by -1. -y/-1=14/-1 And, our result... y=-14

1/2mvi^2+mghi=1/2mvf^2+mghf is the equation. M can be cancelled out. Substitute quantities. Assume vi is 0. Gravity is 9.8. Vf is 1.9. Hf is 0 1/2x0+9.8hi=1/2(1.9^2)+9.8x0 9.8hi=1.81 Hi=.185m

No. To test if a number is divisible by 8: * first all multiples of 8 are even, so the number must be even; * then: add 4 times the hundreds digit to twice the tens digit to the ones digit - if this sum is divisible by 8, then so is the original number. As the test can be applied to the sum, repeating this summing until a single digit remains, only if this single digit is 8 is the original number divisible by 8. For 100: 4x1 + 2x0 + 0 = 4 which is not 8, so 100 is not divisible by 8.

In normal counting (termed Arabic notation) each digit position is greated than the one to its right by a factor of ten. So 2045 is 1x5 + 10x4 +100x0 + 1000x 2 Another way to show the same sum would be: 100x5 + 101x4 + 102x0 + 103x2 In binary we use 2 instead of 10. We only need the digits 1 and 0, just as with normal numbers we don't need any digit higher than 9. So 1100100 would be: 20x0 + 21x0 + 22x1 + 23x0 + 24x0 + 25x1 + 26x1 We can work out all those powers and we get: 1x0 + 2x0 + 4x1 + 8x0 + 16x0 + 32x1 + 64x1 That simplifies to: 4 + 32 + 64 = 100

cBi = coefficients of the current basic variables in the objective function. ... XB = solution values of the basic variables. zj-cj = index row. Or Relative Cost factor The rules used for the construction of the initial simplex table are same in both the maximization and the minimization problems.

0 always wins e.g 1x0=0, 2x0=0 and so on... 1 always lets the other win e.g 1x1=1, 2x1=2 and so on... 2 goes up in twos e.g 2 4 6 8 10 and so on... 3 goes up in three e.g 3, 6, 9, 12, and so on... 4 doble the answers of 2 e.g 4, 8, 12, 16, 20 and so on... 5 the answers always either end in 0 or 5 e.g 5. 10. 15, 20 and so on... 6 is double 3 7 goes up in 7 8 is double 4 9 the answers added together equal 9 e.g 7x9=63 6+3=9 and so on... 10 always ends in 0 *11 the same as what you times it by but add another number e.g1x11=11 77x11=77* 12 the answer goes up in 12 *Also there is another trick for 11 look, 54x11=594 49x11=539 here is how i worked it out... 54x11=? 5+4=9, so put 9 in between 5 and 4, so it becomes 594 49x11=? 4+9=13, so take the 1 from 13 and add it to 4 so it is 5, then put the 3 from 13 in the middle and then add the 9 from 49 at the end so it becomes 539 hope it helped xxxxxxxxxxxxx