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How do you differentiate cos squared x?
use the double angle formula for cos(2x) which is: cos(2x)=2cos^2(x)-1 by this relation cos^2(x)=(cos(2x)+1)/2 now we'd integrate this instead this will give sin(2x)/4+x/2 =) hope this helps
What is the answer of the questions Differentiate X Squared and How?
Differentiating x^2 can be accomplished by using the Power Rule. This provides that d/dx (x^2)=2x
What is x x 2x?
2x+x is 3x
What is the sum of 2x plus 1 and x times x minus 2x plus one?
(2x + 1) + (x*x - 2x + 1) = x^2 + 2x - 2x + 1 + 1 = x^2 + 2
Why is 2x cubed different from 2x times 2x times 2x?
2X * 2X * 2X = 8X^3 2X^3 is saying 2*( X * X * X) = 2X^3
How do you differentiate x2?
The derivative with respect to x of any term in this format: axn is equal to: nax(n -1) so in the case of x2, the answer will be: 2x(2 - 1) = 2x1 = 2x
Differentiate sin x with respect to x?
cos x
How do you differentiate 2 to the power x with respect to x?
The answer is ln(2)2x where ln(2) is the natural log of 2. The answer is NOT f(x) = x times 2 to the power(x-1). That rule applies only when the exponent is a constant.
Differentiate cos x with respect to x?
d/dx(cos x) = -sinx
What is the derivative of square root 2x-x2?
0
What is the derivative of 2x with respect to x?
d/dx(2x) = 2 simple power rule
What is the slope of the tangent line at x squared plus 2x?
Differentiate term by term. d/dx[X2 + 2X) = 2X + 2 slope(m) = 2 ------------------
How do you differentiate x sinx with respect to y?
If you actually mean "... with respect to x", and that y is equal to this function of x, then the answer is:y = x sin(x)∴ dy/dx = sin(x) + x cos(x)
How do you differentiate cos squared x?
use the double angle formula for cos(2x) which is: cos(2x)=2cos^2(x)-1 by this relation cos^2(x)=(cos(2x)+1)/2 now we'd integrate this instead this will give sin(2x)/4+x/2 =) hope this helps
What is the answer of the questions Differentiate X Squared and How?
Differentiating x^2 can be accomplished by using the Power Rule. This provides that d/dx (x^2)=2x
What is the differentiation of y with respect to x for x equals y exponent y?
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
How do you differentiate 0.5lnx?
1/2x
