x2 + 2x - 38 = 0 ∴ x2 + 2x + 1 = 39 ∴ (x + 1)2 = 39 ∴ x + 1 = ±√39 ∴ x = -1 ±√39
This is 41x
2x + 6 + 9x = 39 11x + 6 = 39 11x = 39 - 6 11x = 33 x = 3
2x + 24 = 9x - 39= 2x + 63 = 9x= 63 = 7x= x = 9
8x+39 = 2x-15 6x = -54 x = -9
No.
4x-39 = 2x+3, 4x-2x = 42 x=21
If I understand the question correctly: 2x=39 then x=39/2 or x=19.5
The closest to a solution you can come is:2x + y = 39
4
2x+3=9 x
The diagonals will be equal and so: 4x-47 = 2x+31 => 4x-2x = 31+47 => 2x = 78 Therefore the value of x is: x = 78/2 => x = 39