x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
-16
f'(x)xy=yx(y-1) f'(x)2=2x1=2x
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Divide by 'x'; x2+xy/x = x(x+y)
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
(x - 1)(2x + y)
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
(x + 4)(y - 2)
(x + 4)(y - 2)
(x + 4)(y - 2)
xy(3x - 2y)(2x + 3y)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
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