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Q: What is 2x squared minus 3x minus 9 equals 0?

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3x2 + 2x - 8 = 0 is a quadratic equation.

x(3x - 2)

(x + 3)(3x - 2)

3x=2x-12x=-12

3x2 - 2x - 5 = (3x - 5)(x + 1) = 0 gives a solution of x = 5/3 or -1. Was that what you wanted?

-3X

(x - 2)(2x + 7)

(3x + 2)(2x - 3)

5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.

3x(2x + 1)

2(2x-11)(3x+5)

It is: (2x+3)(3x-8) when factored

I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.

The minimum value of the parabola is at the point (-1/3, -4/3)

3x+7=2x-5 x=-12

(2x + 1)(3x - 4)

3x squared - x squared = 2x squared

3x - 2x + 4 = 0 3x - 2x = -4 x = -4

6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)

The factors are -1(2x + 1)(3x + 4)

Yes.

An equation where x equals 3.

6 - x + 7 - 3x - 5 = -2x - 10 ∴ x + 3x - 2x = 6 + 7 - 5 + 10 ∴ 2x = 18 ∴ x = 9

It is: (3x+4)(2x-3) when factored

2x+3y=13 3x-y=3 x=2