(x + 3)(3x - 2)
(x - 2)(2x + 7)
It is: (2x+3)(3x-8) when factored
The factors are -1(2x + 1)(3x + 4)
3x squared minus 25x minus 28
It is: (3x+4)(2x-3) when factored
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
3x(6x - 1)
(x-3)(3x+1)
6x2 + 10x = 2x*(3x + 5)
3x(2x + 1)