Q: What is 300-7 4 (3 5) 27?

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Factors of 4: 1, 2, 4Factors of 3: 1, 3Factors of 5: 1, 5Factors of 8: 1, 2, 4, 8Factors of 27: 1, 3, 9, 27GCF (4, 3, 5, 8, 27) = 1

5 3/10 + 22 5/10 = 27 8/10 (or 27 4/5)

(4/9) / (3/5) = (4/9) * (5/3) = 20/27

5 - 5/3 + 5/9 - 5/27 + ... = 5 + 5(-1/3)¹ + 5(-1/3)² + 5(-1/3)³ + ... The required sum is an infinite GP with initial term a = 5, and common difference r = -1/3 As |r| < 1, the sum can be found from sum = a/(1 - r) → 5 - 5/3 + 5/9 - 5/27 + ... = 5/(1 - (-1/3)) = 5/(1 + 1/3) = 5/(4/3) = 5 × 3/4 = 15/4 = 3¾

270000 = 27 x 10000 = 27 x 10^4 = 27 x 2^4 x 5^4 = 2^4 x 3^3 x 5^4

Related questions

3-4, 4-2, 5-5

Factors of 4: 1, 2, 4Factors of 3: 1, 3Factors of 5: 1, 5Factors of 8: 1, 2, 4, 8Factors of 27: 1, 3, 9, 27GCF (4, 3, 5, 8, 27) = 1

5 3/10 + 22 5/10 = 27 8/10 (or 27 4/5)

63/4 * 3/5 = 27/4 * 3/5 = 81/20 = 41/20

i dont know

3/4 = 0.75 0.75 x 36 = 27 27 is 3/4 of 36. Since 36 is a multiple of 4, you could also divide by four 36/4=9 and then multiply the quotient by 3, since you are trying to find 3 parts of 4 total. 9*3=27

(4/9) / (3/5) = (4/9) * (5/3) = 20/27

5 - 5/3 + 5/9 - 5/27 + ... = 5 + 5(-1/3)¹ + 5(-1/3)² + 5(-1/3)³ + ... The required sum is an infinite GP with initial term a = 5, and common difference r = -1/3 As |r| < 1, the sum can be found from sum = a/(1 - r) → 5 - 5/3 + 5/9 - 5/27 + ... = 5/(1 - (-1/3)) = 5/(1 + 1/3) = 5/(4/3) = 5 × 3/4 = 15/4 = 3¾

3,007 divided by 5 is 601.4 or 601 with remainder 2.

3(5-x) = 27 15 - 3x = 27 15 - 3x + 3x = 27 + 3x 15 = 27 + 3x 15 - 27 = 27 - 27 + 3x -12 = 3x -4 = x To check 3(5- -4) ? 27 15 - -12 ? 27 15 + 12 = 27

(14/5) / (11/3) = (9/5) / (4/3) = (9/5) * (3/4) = 27/20 = 17/20

combined value = 27 points. 2+3+4+5+6+7=27