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Factors of 4: 1, 2, 4Factors of 3: 1, 3Factors of 5: 1, 5Factors of 8: 1, 2, 4, 8Factors of 27: 1, 3, 9, 27GCF (4, 3, 5, 8, 27) = 1
5 3/10 + 22 5/10 = 27 8/10 (or 27 4/5)
(4/9) / (3/5) = (4/9) * (5/3) = 20/27
5 - 5/3 + 5/9 - 5/27 + ... = 5 + 5(-1/3)¹ + 5(-1/3)² + 5(-1/3)³ + ... The required sum is an infinite GP with initial term a = 5, and common difference r = -1/3 As |r| < 1, the sum can be found from sum = a/(1 - r) → 5 - 5/3 + 5/9 - 5/27 + ... = 5/(1 - (-1/3)) = 5/(1 + 1/3) = 5/(4/3) = 5 × 3/4 = 15/4 = 3¾
270000 = 27 x 10000 = 27 x 10^4 = 27 x 2^4 x 5^4 = 2^4 x 3^3 x 5^4