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The problem is incomplete, as b is a variable.
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Absolute value of x-3 divided by 2 equals 10?
|x-3|/2=10 |x-3|=20 |a|=b means a=b or a=-b Then : x-3=20 or x-3=-20 So: x=23 or x=-17
What are a and b if a x B-Cubed equals 54?
54 = 2 x 3³ So, if a and b are integers, a=2 and b=3
Is 3 over 4 x b the same as 3xb qver 4?
It is difficult to answer the question because it is still ambiguous. Putting brackets in helps. So: (3 over 4) x b = 3/4*b = 3*b / 4 YES but 3 over (4 x b) = 3/(4*b) is not 3/4*b
How to factorise I x power 6 - y power 6 2 x power 12- y power 12?
Explanation: The difference of squares identity can be written: a 2 − b 2 = ( a − b ) ( a b ) The difference of cubes identity can be written: a 3 − b 3 = ( a − b ) ( a 2 a b b 2 ) The sum of cubes identity can be written: a 3 b 3 = ( a b ) ( a 2 − a b b 2 ) So: x 6 − y 6 = ( x 3 ) 2 − ( y 3 ) 2 = ( x 3 − y 3 ) ( x 3 y 3 ) = ( x − y ) ( x 2 x y y 2 ) ( x y ) ( x 2 − x y y 2 ) If we allow Complex coefficients, then this reduces into linear factors: = ( x − y ) ( x − ω y ) ( x − ω 2 y ) ( x y ) ( x ω y ) ( x ω 2 y ) where ω = − 1 2 √ 3 2 i = cos ( 2 π 3 ) sin ( 2 π 3 ) i is the primitive Complex cube root of 1 .
How do you divide two numbers that are in scientific notation?
For example, (4.1076 x 10^3)/(2.8 x 10^4) = (4.1076/2.8) x [10 ^(3 - 4)] = 1.467 x 10^-1 or (4.1076 x 10^3)/(2.8 x 10^-4) = (4.1076/2.8) x [10 ^(3 - -4)] = 1.467 x 10^7
What the LCM of 63 and 76?
Factor them. 2 x 2 x b x b = 4b2 2 x 3 x b x b x b = 6b3 Combine the factors, eliminating duplicates. 2 x 2 x 3 x b x b x b = 12b3, the LCM
Absolute value of x-3 divided by 2 equals 10?
|x-3|/2=10 |x-3|=20 |a|=b means a=b or a=-b Then : x-3=20 or x-3=-20 So: x=23 or x=-17
Examples of cube of a binomial?
(ax + b)^3 = a^3*x^3 + 3*a^2*x^2*b + 3*a*x*b^2 + b^3. Sorry, but it is so clumsy doing this without superscripts!
A and b are prime numbers ab3 equals 54 find the values of a and b?
54 = 2 x 3 x 3 x 3 = 2 x 33. Thus if ab3 = 54 and a, b are prime, then a=2, b=3.
What is the greastest common factor of 24 and 40?
Ascertain the prime and unknown quantity factors of both expressions. 40a3b = 2 x 2 x 2 x 5 x a x 3 x b = 23 x 3 x 5 x a x b. 24a3b5 = 2 x 2 x 2 x 3 x a x 3 x b x 5 = 23 x 32 x 5 x a x b. The common factors are 23, 3, 5, a and b The Greatest Common Factor is 23 x 3 x 5 x a x b = 120ab = 40a3b
What is -a x 2 x b-3?
5
What are a and b if a x B-Cubed equals 54?
54 = 2 x 3³ So, if a and b are integers, a=2 and b=3
What is the sum of the prime factors of 81?
As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
Factoring x cubed?
b represents a number ^ represents raised to a power (x - b)(x^2+ bx +b^2) For example: (X^3 - 27) (x - 3)(x^2 + 3x + 3^2) = (x - 3)(x^2 + 3x + 9)
What is ab times b?
(a x b)^b =ab x b^2 =ab^3
How do you factor the monomial 81b?
3 x 3 x 3 x 3 x b = 81b
Is 3 over 4 x b the same as 3xb qver 4?
It is difficult to answer the question because it is still ambiguous. Putting brackets in helps. So: (3 over 4) x b = 3/4*b = 3*b / 4 YES but 3 over (4 x b) = 3/(4*b) is not 3/4*b
