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Absolute value of x-3 divided by 2 equals 10?
|x-3|/2=10 |x-3|=20 |a|=b means a=b or a=-b Then : x-3=20 or x-3=-20 So: x=23 or x=-17
What are a and b if a x B-Cubed equals 54?
54 = 2 x 3³ So, if a and b are integers, a=2 and b=3
Is 3 over 4 x b the same as 3xb qver 4?
It is difficult to answer the question because it is still ambiguous. Putting brackets in helps. So: (3 over 4) x b = 3/4*b = 3*b / 4 YES but 3 over (4 x b) = 3/(4*b) is not 3/4*b
How to factorise I x power 6 - y power 6 2 x power 12- y power 12?
Explanation: The difference of squares identity can be written: a 2 − b 2 = ( a − b ) ( a b ) The difference of cubes identity can be written: a 3 − b 3 = ( a − b ) ( a 2 a b b 2 ) The sum of cubes identity can be written: a 3 b 3 = ( a b ) ( a 2 − a b b 2 ) So: x 6 − y 6 = ( x 3 ) 2 − ( y 3 ) 2 = ( x 3 − y 3 ) ( x 3 y 3 ) = ( x − y ) ( x 2 x y y 2 ) ( x y ) ( x 2 − x y y 2 ) If we allow Complex coefficients, then this reduces into linear factors: = ( x − y ) ( x − ω y ) ( x − ω 2 y ) ( x y ) ( x ω y ) ( x ω 2 y ) where ω = − 1 2 √ 3 2 i = cos ( 2 π 3 ) sin ( 2 π 3 ) i is the primitive Complex cube root of 1 .
How do you divide two numbers that are in scientific notation?
For example, (4.1076 x 10^3)/(2.8 x 10^4) = (4.1076/2.8) x [10 ^(3 - 4)] = 1.467 x 10^-1 or (4.1076 x 10^3)/(2.8 x 10^-4) = (4.1076/2.8) x [10 ^(3 - -4)] = 1.467 x 10^7
