- 2 - 3i
s3 - 3s2 + 9s - 27 = s2(s - 3) + 9(s - 3) = (s - 3)(s2 + 9) or = (s - 3)(s2 - (9i2) = (s - 3)(s - 3i)(s + 3i) if you want to find for what values of s the expression equals to zero, then this happens when s - 3 = 0 or s - 3i = 0 or s + 3i = 0 s = 3, ±3i
nine to the sixth power is 531441.
99 to the sixth power is 941,480,149,401
0 + 3i
11
0.3 to the sixth power equals 0.000729
1.028 to the sixth power is 1.18020836358(rounded).
25 to the sixth power equates to 244,140,625
27 to the sixth power equals 387,420,489
The complex conjugate of 2-3i is 2+3i.
(3i)5 = 35 x i5 = 243 x i2 x i2 x i = 243 x (-1) x (-1) x i = 243i