It depends on what the denominator was to start with: a surd or irrational or a complex number. You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected. If a and b are rational numbers, then conjugate of sqrt(b) = sqrt(b) conjugate of a + sqrt(b) = a - sqrt(b), and conjugate of a + ib = a - ib where i is the imaginary square root of -1.
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
The concept of conjugate is usually used in complex numbers. If your complex number is a + bi, then its conjugate is a - bi.
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To find the complex conjugate change the sign of the imaginary part: For 11 + 5i the complex conjugate is 11 - 5i.
The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
"Conjugate" usually means that in one of two parts, the sign is changed - as in a complex conjugate. If the second part is missing, the conjugate is the same as the original number - in this case, 100.
The conjugate acid of NO2- is HNO2 (nitrous acid).
The conjugate acid of LiOH is considered Li+.
The conjugate acid of H2O is H3O+ (hydronium ion). When an acid donates a proton, it forms its conjugate base, and when a base accepts a proton, it forms its conjugate acid.
The conjugate of 6 + i is 6 - i.
It depends on what the denominator was to start with: a surd or irrational or a complex number. You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected. If a and b are rational numbers, then conjugate of sqrt(b) = sqrt(b) conjugate of a + sqrt(b) = a - sqrt(b), and conjugate of a + ib = a - ib where i is the imaginary square root of -1.
The conjugate base of NH3 is NH2-, formed by removing a proton (H+) from NH3.
The conjugate base of HSO3- is SO32-.
the conjugate 7-2i
The conjugate base for CH3CH2COOH is CH3CH2COO-.