n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
3
The GCF is 3n.
Add 7 to each side: 3n2 = 7 Divide each side by 3: n2 = 7/3 n = sqrt 7/sqrt 3, ie just over 1.5
3n2-8n+4 = (3n-2)(n-2) when factored
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
3
Formula: (Hg2)3N2
2NaN ---> 2Na + 3N2
The GCF is 3n.
-((3n - 1)(n + 3))
Maybe: [Cd(NH3)5]3N2
(3n+2)(n+1)
3n2 + 1Hope this helps :)
The chemical equation is:2 NaN3 = 2 Na + 3N2
KNO3