n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
3
The GCF is 3n.
Add 7 to each side: 3n2 = 7 Divide each side by 3: n2 = 7/3 n = sqrt 7/sqrt 3, ie just over 1.5
-4n3 + 8n2 - 4n + 7
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
3
Formula: (Hg2)3N2
2NaN ---> 2Na + 3N2
The GCF is 3n.
-((3n - 1)(n + 3))
Maybe: [Cd(NH3)5]3N2
(3n+2)(n+1)
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence does not appear to follow a simple arithmetic or geometric progression. Therefore, it is likely following a pattern involving squares or cubes of numbers. By examining the differences between consecutive terms, we can deduce the pattern and determine the nth term. In this sequence, the differences between consecutive terms are 9, 15, 21, which are not constant. This suggests a more complex pattern, possibly involving squares or cubes of numbers.
The chemical equation is:2 NaN3 = 2 Na + 3N2
Add 7 to each side: 3n2 = 7 Divide each side by 3: n2 = 7/3 n = sqrt 7/sqrt 3, ie just over 1.5