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Q: How do you get 24 using 8 8 6 and 1 once?

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To get 24 using 1 3 4 and 6 once you do 6 times 4

6 x (5 + 1 - 2) = 6 x 4 = 24

It can be done by: (9-5) times 6 times 1 = 24

96 x 1/4 = 24

2*(6/6 + 11) = 2*(1 + 11) = 2*12 = 24. Simple!

6(5 - 7/7) = 6(5 - 1) = 6 x 4 = 24

It is: 6*(5-2)+6 = 24.

(6 x 5) - (6 x 1) = 30 - 6 = 24

6(7 - (2 + 1)) = 24 2 plus 1 equals 3. 7 minus 3 equals 4. 4 times 6 equals 24.

6/(1-3/4)=24

(9-4-1)*6=24

How about: (9+3)+6*(1+1) = 24

It can be done by: 9 times (1+1) plus 6 = 24

(4+5-6)x8=24

6 * (7 - 1 - 2) = 6*4 = 24

(-6)*(-5+(-7)/(-7)) = 24

A possibility is: (8-3-1) times 6 = 24

2*(4! - 3! + 1) = 2*(24 - 6 + 1) = 2 * 19 = 38

6*5*1-6

(8 - 4) x 6 x 1 = 4 x 6 = 24

78 - (6 x 9) = 78 - 54 = 24

6*(1 + 7 - 4) = 6*(8 - 4) = 6*4 = 24

(6 x 13) - (6 x 9) = 78 - 54 = 24

9 +16 -1 = 24

The only way I know how to do it is 12+13=25, 6 divided by 6=1, and 25-1=24