4 1/2 x 53 1/3 = 240
20
1/2
1 with remainder 31.
1, 2, 53, 106 1, 2, 53, 106 1,2,? 2 53 1 106
1/4 times 2 is 1/2
The question, in algebraic notation, is (34-x)/(53-x) = 1/2. Cross-multiplying gives us: 2(34-x) = 53-x; distributing the 2 gives us: 68-2x = 53-x; adding 2x to both sides yields: 68 = 53+x; subtracting 53 from both sides gives the answer: 15 = x; Putting that answer back into the original problem: (34-15)/(53-15) = 19/38 = 1/2
1
It is: 2 and 1/3 times 1 and 1/3 = 3 and 1/9
1/5
The answer to the math problem of -3 over 8 times 1 over 2 is -3/16.
1/2 *1/4= 1/8
106