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The question, in algebraic notation, is (34-x)/(53-x) = 1/2. Cross-multiplying gives us: 2(34-x) = 53-x; distributing the 2 gives us: 68-2x = 53-x; adding 2x to both sides yields: 68 = 53+x; subtracting 53 from both sides gives the answer: 15 = x;

Putting that answer back into the original problem: (34-15)/(53-15) = 19/38 = 1/2

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Q: What number can be subtracted from both the numerator and the denominator of 34 over 53 to equal 1 over 2?
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