4*(n + 1) = 6*n*3
It depends what the n stands for as a variable.
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
m^4 n^5 - m^20 n^21
It is 4n
It is 3*abs(n - 6) + 4*n
9(4+n)Nine times the sum of 4 and a number is an expression and can not be evaluated.
It is 8*(-4)N which is -32N
The question is ambiguous. Does "2 over 3 times n" mean 2/(3*n) or (2/3)*n
4*(n + 6008)
10n = -30 n = -3
You have one linear equation in two unknown variables: A and n. There can be no solution.
If you are looking for an algebraic expression then here is the answer:Let the number be N4(N+4) is the expression.
10000. Ten multiplied by itself n times is 1 followed by n zeros.
4(N-3) is the formula, do the math from there and you get "N-3"
n cubed = n times n times n
n = number. 47 * n + 4 or 47(n + 4)
(-7)n - 4 = 13 - (6)n
Yes. By definition a multiple of 8 is any number that can be expressed as 8*n, where n is an integer. But 8n=4*(2*n), and 2*n is an integer, when n is an integer. Because 8n equals four times an integer, 8n is a multiple of 4.