(n+4)2
m^4 n^5 - m^20 n^21
9(4+n)Nine times the sum of 4 and a number is an expression and can not be evaluated.
It is 3*abs(n - 6) + 4*n
4(N-3) is the formula, do the math from there and you get "N-3"
4*(n + 1) = 6*n*3
9
40
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
n = number. 47 * n + 4 or 47(n + 4)
10n = -30 n = -3
It is 4n
(n+4)2
m^4 n^5 - m^20 n^21
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
9(4+n)Nine times the sum of 4 and a number is an expression and can not be evaluated.