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What else can I help you with?
How do you write two times n more than four?
(n+4)2
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
Nine times the sum of 4 and a number?
9(4+n)Nine times the sum of 4 and a number is an expression and can not be evaluated.
What is Three times the difference of the number and six increased by four times the number?
It is 3*abs(n - 6) + 4*n
What is four times the sum of a number and 3?
4(N-3) is the formula, do the math from there and you get "N-3"
What is n times 4 equals 9 plus n?
9
What is the expresstion of 4 times the difference of a number an 1 is equal to 6 times the sum of a number times 3?
4*(n + 1) = 6*n*3
what is n times by 4 pls answer?
40
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
How do you simplify 16 times 2 power of n times 10 times 2 to the power of n?
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
What is expression the four seven times four more than a number?
n = number. 47 * n + 4 or 47(n + 4)
The sum of 6 times a number n and 4 times a number n is -30 what is the number?
10n = -30 n = -3
How many different groups of 4 can be made from 17 students?
To find the number of different groups of 4 that can be made from 17 students, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). In this case, ( n = 17 ) and ( r = 4 ). Therefore, the calculation is ( C(17, 4) = \frac{17!}{4!(17-4)!} = \frac{17!}{4! \times 13!} = \frac{17 \times 16 \times 15 \times 14}{4 \times 3 \times 2 \times 1} = 2380 ). Thus, there are 2,380 different groups of 4 that can be formed from 17 students.
What is 4 times some number n?
It is 4n
How do you write two times n more than four?
(n+4)2
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
