Assume that we have 4x² - 8.
There are many way to describe it.
• 4x² - 8 is a binomial because that expression has two terms.
• It's also a polynomial because it consists of many finite number of terms!
On the other hand if you really meant 4*2-8 then the answer is 0
It's best if you include some details for the question you have asked. Thank you!
If your equation is 5x-2=4x+4 Then this is how you solve it... 5x-2=4x+4 5x-2+2=4x+4+2 5x=4x+6 5x-4x=4x-4x+6 x=6 Your x=6
ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X
4x * x = 4x^2
-4x-2+2=-2+2. -4x/-4=0/-4 x=0
4x + 2 + 6 = 2 4x + 8 = 2 4x = -6 x = -6/4 = -3/2
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
4x-34(2) =
-4x + 2 = 6 -4x = 6 - 2 -4x = 4 x = 4 / -4 x = -1
It is -4x - 4
2 and 4x + 1
4x^2 = 2 * 2 * x * x
k*tan[√(4x)]=k*tan[(4x)1/2], where k is a constant:Multiplying by a constant, multiply the derivative of u by the constant c: d/dx d/dx(cu)=c*du/dxd/dx(k*tan[(4x)1/2])=k*d/dx(tan[(4x)1/2])-The derivative of tan[(4x)1/2] is:d/dx(tan u)=sec2(u)*d/dx(u)d/dx(tan[(4x)1/2])=sec2([(4x)1/2])*d/dx([(4x)1/2])d/dx(tan[(4x)1/2])=sec2(2√x)*d/dx([(4x)1/2])d/dx(k*tan[(4x)1/2])=k*{sec2(2√x)*d/dx([(4x)1/2])}-The derivative of (4x)1/2 is:Chain rule: d/dx(ux)=x(u)x-1*d/dx(u)d/dx(4x)1/2=(1/2)*(4x)1/2-1*d/dx(4x)d/dx(4x)1/2=(1/2)*(4x)-1/2*4d/dx(4x)1/2=4/[2(4x)1/2]d/dx(4x)1/2=4/[2(2√x)]d/dx(4x)1/2=4/[4√x]d/dx(4x)1/2=1/(√x)d/dx(k*tan[(4x)1/2])=k*sec2(2√x)*(1/√x)d/dx(k*tan[(4x)1/2])=[k*sec2(2√x)]/√x