2 is a solution of the equation, but not if it's an inequality.
If the inequality is > (greater than) or >= (greater than or equal to), then there are an infinite number of solutions. So let the inequality be < (less than) or <= (less than or equal to) x = 1: 5y <= 16 so y = 1, 2 or 3 x = 2: 5y <= 12 so y = 1 or 2 x = 3: 5y <= 8 so y = 1 x >= 4: 5y <= 4 no solution. So whether the inequality is < or <= there are 6 ordered pairs.
(4x^3 + 2x^2 + 3x + 4)/(x + 4) = 4x^2 - 14x + 59 - 232/(x + 4)
If your equation is 5x-2=4x+4 Then this is how you solve it... 5x-2=4x+4 5x-2+2=4x+4+2 5x=4x+6 5x-4x=4x-4x+6 x=6 Your x=6
It's an equation. Specifically, a linear equation in ' x '.Here's the solution for ' x ':4x + 7 = -3 - x5x + 7 = -35x = -10x = -2
the solution for the inequality 4x + 2 - 6x < -1 was x < 3/2
1/2 or .5
The equation 4x + 5 = 2 has the solution 4x = -3 and x = - 3/4 (minus 3/4).
2
It simplifies to: -4x-12
no its not a solution
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
If the equations are 8x + 7y = 37, and 2y = 4x -2 then the answer is yes.
If you mean: x+4x--9 = x+1 then 4x = -8 and x = -2
-2
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
3x + (-2 + 4x) = -2 + 7x