Q: What is 55 14m - 2n 3p?

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14M + 2n - 6M + 11n = 8M + 13n

6p divide by 3p = 2

It is: 3p+5p = 8p

17

100 - 3p = 88 -3p = 88 - 100 -3p = -12 p= (-12/-3) p = 4 so 100 - 3 * 4 = 88

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14M + 2n - 6M + 11n = 8M + 13n

Let the two consecutive integers be n and n+1. Then, n + (n + 1) < 55 2n + 1 < 55 2n < 55 - 1 : 2n < 54 n < 27 The Inequality Statement can therefore be modified to show that for two consecutive integers to be less than 55 then the smaller integer must be less than 27.

10-14m = -4

43km 14m to kilometers

(Term)n = 59 - 2n

The easiest way to do this is to use 'n' as one integer. Now, the next one needs to be consecutive, so we can make the second integer 'n+1' n + (n+1) = 55 Now all we do is start simplifying 2n + 1 = 55 2n = 55 -1 2n = 54 n = 27 Since n = 27, the first integer will be 27. And we stated that the second is 'n+1', so the second would be 28. Double check, 27 + 28 = 55 So, our integers are 27 and 28.

3p

6p divide by 3p = 2

3p - 6 > 21 3p - 6+6 > 21+6 3p > 27 3p/3 > 27/3 p>9 this WILL help

m² - 14m + 48 = (m - 6)(m - 8)

It is: 3p+5p = 8p

2n+2n equals 4n