m² - 14m + 48 = (m - 6)(m - 8)
14m x 8m x 6m = 672 m^3
270
510 cm or 5.10 m
If it's a rectangle, 48 m.
m-2+1-2m+1 When simplified: -m
7 - 14m
7 x m = 7m2 x 7 x m = 14m
(m + 5)(3m - 1)
m+36
14m x 8m x 6m = 672 m^3
m= -48
14m
14m * 100cm/1m = 1400cm
To find the greatest common factor (GCF) of 14m^2 and 21m, we first need to factor each term. The factors of 14m^2 are 1, 2, 7, 14, m, and m. The factors of 21m are 1, 3, 7, 21, m, and 1. The common factors between the two terms are 1, 7, and m. Therefore, the greatest common factor of 14m^2 and 21m is 7m.
4M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 14M + 5 = 9Subtract 5 from both sides: 4M = 4Divide both sides by 4: M = 1
To simplify the expression ( 14m + 6n - 4m + 8n ), first combine like terms. For the ( m ) terms: ( 14m - 4m = 10m ). For the ( n ) terms: ( 6n + 8n = 14n ). Therefore, the simplified expression is ( 10m + 14n ).
This is a hyperbola. It is best approached using Fermat's factorisation method. Seefermat-s-factorization-methodor google wikepedia. I don't know of any faster approach.