120
11 times 5 24 times = 1,320
24*5=120
5 times 24 = 120.
80 x 24 x 5 = 9,600
300 / 60 = 5
To find the number of combinations of 5 students that can be chosen from 24 students, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 24 ) and ( k = 5 ), so the calculation is ( C(24, 5) = \frac{24!}{5!(24-5)!} = \frac{24!}{5! \cdot 19!} = \frac{24 \times 23 \times 22 \times 21 \times 20}{5 \times 4 \times 3 \times 2 \times 1} = 42504 ). Therefore, the teacher can choose from 42,504 different combinations of 5 students.
24/5 = 4 and 4/5
of means times. so its 1/3 times 5/8 which = 5/24
It is about: 1.888175023^5
three eights times 5 = 3*8 times 5 = 24 times 5 = 120
5/8 x 24 - is 15