6 factorial (notated as 6!) is multiplying every whole number from 1 to 6 together.
6! = 6 x 5 x 4 x 3 x 2 x 1 = 720.
9x-11 = 6x+1 9x-6x = 1+11 3x = 12 x = 4
6x(1+4)
-2
If: 6x-4+7 = 5 Then: x = 1/3
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
There is no simplification. It is sqrt(6X +4)There is no simplification. It is sqrt(6X +4)There is no simplification. It is sqrt(6X +4)There is no simplification. It is sqrt(6X +4)
40=4-6x 40-(4)=4-6x-(4) 36=-6x -6=x
6x+2y=4 gives y=2-(1/3)x
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
-6x-4-8 = -6x -12
4x-6 = -6x-4 4x+6x = 6-4 10x = 2 x = 2/10 x = 1/5 Regards, A Pakistani!
x=4 y=1 Therefore, 6x+5y=? Just substitute, and get 6*4+5*1=29