x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:
No because the answers are 6 and 4 respectively.
sqrt(4) = 2 sqrt(9) = 3 Therefore, the square root of 4 plus the square root of 9 is equal to 2 + 3 = 5.
4 square root 3 + 4 cube root 3 is 12.6972015
It is: 4+7 = 11
root (6x - 2) = 4 therefore 6x - 2 = 16 therefore 6x = 16 + 2 therefore x = 3
If the square root of 6x-2=4 than we can square both sides and we have 6x-2=16 or 6x=18 and the solution set is the set that contains the number 3.
x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
No because the answers are 6 and 4 respectively.
Squareroot of 4 + Squareroot of 4 + Squareroot of 4 + 4=2+2+2+4=10
sqrt(4) = 2 sqrt(9) = 3 Therefore, the square root of 4 plus the square root of 9 is equal to 2 + 3 = 5.
4 square root 3 + 4 cube root 3 is 12.6972015
44 divided by (the square root of 4 plus the square root of 4) or 4 divided by point 4 plus 4/4
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It is: 4+7 = 11
15