√18xy = √(9*2xy) = √9*√2xy = 3*√(2xy)
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
4xy - 2xy
0.3333
Neither of those expressions is a binomial. [ 2y + 2xy ] is a binomial.
2xy
(2xy)x=2x2y
Since 2xy is a factor of 2x2y, it is automatically the GCF.
2xy + 6xy = 8xy
(x + 4y)(x - 6y)
√18xy = √(9*2xy) = √9*√2xy = 3*√(2xy)
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
The three terms are: -3xy2, 2xy and -4y3
4xy - 2xy
3xy and 2xy. You can see that 3xy and 2xy have something in common with each other. They both have xy and the end of them. Hope this helped.
(2xy-4x)+ (8y-16)=2xy-4x+8y-16, which factors as 2(x+4)(y-2)
What is : 5xy- x2t + 2xy + 3x2t