yes * * * * * No, it isn't. 2xy = 2 times x times y. Depending on which you mean: 2x2y = 2 times x times 2 times y = 4xy; OR 2x2y = 2 times x times x times y.
8-x2y 8-2xy 2xy-8
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
it means two times x times y.
You can expand (x + y)2 into x2 + 2xy + y2
4xy - 2xy
(x + 4y)(x - 6y)
yes * * * * * No, it isn't. 2xy = 2 times x times y. Depending on which you mean: 2x2y = 2 times x times 2 times y = 4xy; OR 2x2y = 2 times x times x times y.
8-x2y 8-2xy 2xy-8
it would equal 2xy
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
'x' times '2y' is written as '2xy'. In Algebra. Addition is shown as 'a + b' '. Subtraction is shown as 'a - b' Multiplication is shoewn as 'ab' (NB no multiplication sign 'x', as it might be confused with the unknown 'x'. Division is showen as a/b ( like a fraction). NB '2y' means '2' Times 'y' So overall 2 X y X x = 2xy . Notice ; for clarity ,I have put in 'capital ' 'x' for multiplication. However, hopefully you can see that it may become unclear which is the unknown 'x'.
2xy*9 if x=3 and y = 2 2(3)(2)*9 12*9 108 You substitute x and y for their equivalent (3 and 2) then simply multiply 2*x*y, then multiply the answer of that by 9.
15xy-2xy-7x+x=13xy-6x
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
X²+2xy+y²
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.