49v2 + 9 - 42v = 49v2 - 21v - 21v + 9 = 7v(7v - 3) - 3(7v - 3) = (7v - 3)2
It can be simplified to: -7v-1096
the answer is 7v * 5
56v2 + 121v + 63 = 56v2 + 49v + 72v + 63 = 7v*(8v + 7) + 9*(8v + 7) = (8v + 7)*(7v + 9)
If you mean: -33v = 70-7v then v = 70/-26 Otherwise not knowing the plus, minus or equal value of 70 it has no solution
-12=2+5v+2v ---> Add Like terms-12=2+7v ----> Subtract 2 from both sides-14=7v ---> Divide each side by 7-2=v-2=V is your final answer
(6r - 7v)(3r - 2v)
It would just last longer between charges.
v * 7v > 637*v^2 > 63 v^2 > 9 v < -3 or v > 3.
.7v less than unity for DC operation but unity for AC.
See related link.
IF DONE RIGHT MOST LIKLEY 9
The LCM of 7v and 92v is 644v The LCM of 7v9 and 2v is 14v9
Multiply out the brackets and collect the like terms which simplifies to 5w-7v
because the voltage drop.
Your 7V prefix indicates that you have a browning auto-5 magnum shotgun that was made by FN of belguim for browning in 1967.
The resistor required for a 9V power supply for an LED would be 270 Ohms. This assumes that the LED requires 25mA at 2V. The drop across the resistor would be 7V. (9V-2V) By Ohm's law, resistance is voltage divided by current, so 7V divided by 25mA is 280 Ohms. The nearest standard value is 270 Ohms. If you had a low current LED, such as 2.5mA, the resistor would by 2.7K Ohms.
If three resistors draw currents of 1A, 2A, and 4A across an unknown voltage V, then by Ohm's law, the resistances are V/1, V/2, and V/4.Place those three resistors in series, and the net resistance is V/1 + V/2 + V/4, which is 7V/4 ohms.Place a resistance of 7V/4 ohms across a voltage source of V, and (again by Ohm's law) you get a current of V over 7V/4, or 4/7 A.Note that you do not need to know V, because in the end, V cancels out.
There are zero watts in a 7 volt battery. Watts are the product of amps x volts. The amperage of the load connected tot he battery has to be stated. Batteries are usually rated in amp hours.
because1) knee voltage of silicon is .7V where as germanium has .3V 2)silicon breakdown take place at around 200 0C and germanium at 90 0C