There is no solution, as it is not an equation. However it could be simplified to: -18v - 86 or -2(9v + 43)
The next character in the series, "1Z Y2 3X W4 5V" is "U6".
It is: 15+5v
Answer book for simple solutions Common Core mathematics grade 5v
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Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
3 + 5v = -275v = -27 -35v = -30v = -6
12V, 8V, 5V, 3.3V, and 2V.
v = -5
-v + 5 + 6v = 1 + 5v + 3Clean up and combine each side:(-v + 6v) + 5 = (1 + 3) + 5v5v + 5 = 4 + 5vSubtract 5v from each side:5 = 4.There is no solution.No value of 'v' can make [ 5 = 4 ].
By changing the polarity of the source
By changing the polarity of the source
The answer is 1 + 5v.
v=17
4 multiplyed by a number (Variable) plus 5 multiplyed by a number (V) equals 15 4v + 5v = 15 15/5 = v 15/4 = impossibility >_< Sorry :~) v = ImPoSiBiLiTy
+12V, -12V, +5V, -5V, +3.3V +12V, -12V, +5V, -5V, +3.3V