x% = x/100
8/5 (x20 top and bottom)
160/100
therefore 160%
62.5%
15 and 24, respectively.
5/8's
288
144.44%
5/8 of an inch
If s-5=3 then the value of s is 8 !
5/100 or 1/20 or 0.05
No 5/8 is not greater because if you change 3/4 to 6/8 by multiplying by 2 on both sides of the division line, changing 3/4 to eight's, it is one-eighth less than 6/8's
[5(s^2)(t^2)]/40st since it is multiplication you can separate the fraction; = (5/40)(s^2/s)(t^2/t) = (1/8)st or = st/8
Assuming the sides of the triangle a=5, b=5 and c=6, the semiperimeter s=(5+5+6)/2=8. Height d=3 is not necessary if you use Heron´s formula for the area (A): A = [s(s-a)(s-b)(s-c)]1/2 = [8(8-5)(8-5)(8-6)]1/2 = [144]1/2 = 12
5