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How do you factor 9x2-6xy y2-81?
(3x - y)(3x - y) - 81
Square root 9x2 y6?
3x y^3
How do you factorize 9 multiplied by x square plus 24 multiplied by x and y plus 16 multiplied by y square?
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
What is the x and y intercepts of 9x squared plus 12x plus 4?
If y = 9x2 + 12x + 4 Then the y intercept will be when x = 0, which is 4: y = 9(0)2 + 12(0) + 4 y = 0 + 0 + 4 y = 4 The x intercept will happen when y = 0, which we can work out by finding factors of the equation and determining x values that give us a zero y value: 9x2 + 12x + 4 = 0 9x2 + 6x + 6x + 4 = 0 3x(3x + 2) + 2(3x + 2) = 0 (3x + 2)(3x + 2) = 0 (3x + 2)2 = 0 3x + 2 = 0 3x = -2 x = - 2/3 So the x intercept is at -2/3 and the y intercept is at 4.
How do you factor this Y equals x³ plus 3x² - 10x-24 and Y equals -x³ -6x²-3x plus 10?
It can be simplified in the form of: 2x3+9x2-7x-34 = 0
Factor this expression 9x2 - y2?
(3x + y)(3x - y)
What is the factor of 9x2-6xy plus y2?
(3x - y)(3x - y)
How do you factor 9x2-6xy y2-81?
(3x - y)(3x - y) - 81
Square root 9x2 y6?
3x y^3
How do you factor 9x2-6xy plus y2-81?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 (since the first three terms make a perfect square = (3x - y - 9)(3x - y + 9) since the expression now is a difference of two squares.
How would you factor 9x2 - 6xy plus y2 - 81?
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
How do you factorize 9 multiplied by x square plus 24 multiplied by x and y plus 16 multiplied by y square?
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
Factor 9x squared minus 6xy plus y squared minus 81?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
What is 9x squared minus 6xy plus y squared minus 81 factored as?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
What is the x and y intercepts of 9x squared plus 12x plus 4?
If y = 9x2 + 12x + 4 Then the y intercept will be when x = 0, which is 4: y = 9(0)2 + 12(0) + 4 y = 0 + 0 + 4 y = 4 The x intercept will happen when y = 0, which we can work out by finding factors of the equation and determining x values that give us a zero y value: 9x2 + 12x + 4 = 0 9x2 + 6x + 6x + 4 = 0 3x(3x + 2) + 2(3x + 2) = 0 (3x + 2)(3x + 2) = 0 (3x + 2)2 = 0 3x + 2 = 0 3x = -2 x = - 2/3 So the x intercept is at -2/3 and the y intercept is at 4.
How do you factor 3x3-81?
9y-81=9*(y-9)
What is the additive inverse of -7x2 y?
7x2 + y
