9.5 x 4 = 38
95 x 1 = 95 95 x 2 = 190 95 x 4 = 380 95 x 7 = 665 95 + 190 + 380 = 665
1 x 95 = 95 2 x 95 = 190 3 x 95 = 285 4 x 95 = 380 5 x 95 = 475 6 x 95 = 570 7 x 95 = 665 8 x 95 = 760 9 x 95 = 855 10 x 95 = 950 11 x 95 = 1045 12 x 95 = 1140
13x-2+11x+1=95. 24x-1=95 24x=96 x=96/24 x=4 to check it you substitute 4 for x. so the equation would then be... 13(4)-2+11(4)+1=95 52-2+44+1=95 95=95
19. 4 x 19 = 76 5 x 19 = 95
4 x 95 = 380
To solve this, you have to start with the whole of 80, and then take away 95% of 80, or (.95 x 80). 80 - (.95) x 80 = 4 Alternatively, you could do a bit of quick mental algebra to speed it up: 80 - (.95)(80) = 1 x 80 - .95 x 80 = 80(1 - .95) = 80(.05) = 4 Since you take away 95%, you're left with 5%.
If [ x = 95 ],then [ -x = -95 ].
100
Let x = first odd number x + 2 = second odd number,etc. x + (x+2) + (x+4) + (x + 6) + ( x + 8) = 95 5x + 20 = 95 5x = 75 x = 15 15,17,19,21,23
1 x 95, 5 x 19, 19 x 5, 95 x 1 = 95
95/2 x 1/4 = 95/8 or 11 and 7/8
Let's solve this using an equation and some algebra. The original equation will look like this: 95 = x + x+1 + x+2 + x+3 + x+4 I've grouped the plus x's and numbers so that its easier to see. Since the numbers are consecutive, we can determine that the numbers are x through adding 1 through 4 to x for the remaining 4 integers. Now we can simplify the problem. I'll put each step on its own line starting with a repeat of the original equation: 95 = x + x+1 + x+2 + x+3 + x+4 95 = 5x + 10 95 - 10 = 5x + 10 - 10 85 = 5x 85/5 = 5x/5 17 = x So the lowest integer is 17. Now we just count 4 numbers higher to get the remaining 4 of 5 integers. Your answer is 17, 18, 19, 20, 21.