Let's solve this using an equation and some algebra. The original equation will look like this:
95 = x + x+1 + x+2 + x+3 + x+4
I've grouped the plus x's and numbers so that its easier to see. Since the numbers are consecutive, we can determine that the numbers are x through adding 1 through 4 to x for the remaining 4 integers. Now we can simplify the problem. I'll put each step on its own line starting with a repeat of the original equation:
95 = x + x+1 + x+2 + x+3 + x+4
95 = 5x + 10
95 - 10 = 5x + 10 - 10
85 = 5x
85/5 = 5x/5
17 = x
So the lowest integer is 17. Now we just count 4 numbers higher to get the remaining 4 of 5 integers.
Your answer is 17, 18, 19, 20, 21.
The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.
The numbers are -5 and -4.
-1, 1, 3, 5
59, 61,63,65,67
5, 6, 7, 8
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
-4 and -5
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
4 and 5
-3,-4,-5
The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.
The integers are 5, 6, 7 and 8.
The numbers are -5 and -4.
The integers are 3, 4, 5 and 6.
-1, 1, 3, 5
It is -7,-6,-5,-4!
The numbers are -6, -5 and -4.