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Let's solve this using an equation and some algebra. The original equation will look like this:

95 = x + x+1 + x+2 + x+3 + x+4

I've grouped the plus x's and numbers so that its easier to see. Since the numbers are consecutive, we can determine that the numbers are x through adding 1 through 4 to x for the remaining 4 integers. Now we can simplify the problem. I'll put each step on its own line starting with a repeat of the original equation:

95 = x + x+1 + x+2 + x+3 + x+4

95 = 5x + 10

95 - 10 = 5x + 10 - 10

85 = 5x

85/5 = 5x/5

17 = x

So the lowest integer is 17. Now we just count 4 numbers higher to get the remaining 4 of 5 integers.

Your answer is 17, 18, 19, 20, 21.

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Q: The sum of 5 consecutive integers is 95 what are the integers?
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