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It is a sequence of 12 positive integers.
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∙ 9y ago
melaku gezahegn
ODD
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What is 1 over 2 5 over 6?
Without a sign, I'm not sure what you want to have happen to them. 1/2 = 3/6 3/6 + 5/6 = 8/6 = 4/3 or 1 and 1/3 3/6 - 5/6 = -2/6 = -1/3 1/2 x 5/6 = 5/12 1/2 divided by 5/6 = 1/2 x 6/5 = 6/10 = 3/5
Can 1 2 3 and 5 equal 6?
5-3=2 1=2=3 3*2=6
What is 5 and 1 3rd minus 3 and 5 6th?
5 and 1/3 is the same as 5 and 2/6 which makes the sum alot easier; 5 and 2/6 - 5/6 = 4 and 3/6 - 3 = 1 and 3/6 or 1 and 1/2 in short.
What is 8 minus 6 and 3 fifths?
8 - 6 3/5 = (7 + 1) - (6 + 3/5) = (7 - 6) + (1 - 3/5) = 1 + 2/5 = 1 2/5.
What are the steps in subtracting dissimilar fractions with regrouping?
3 1/2=3 3/6=2 6/6+1 5/6=1 1/6 is the final answer - 1 5/6=1 5/6
What is the sample space for rolling a pair of dice?
The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
What are the possible outscomes for a six sided die?
1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P
What is 1 over 2 5 over 6?
Without a sign, I'm not sure what you want to have happen to them. 1/2 = 3/6 3/6 + 5/6 = 8/6 = 4/3 or 1 and 1/3 3/6 - 5/6 = -2/6 = -1/3 1/2 x 5/6 = 5/12 1/2 divided by 5/6 = 1/2 x 6/5 = 6/10 = 3/5
What are the combinations of rolling 2 dice?
In a combination the order does not matter, so they are: 1 1 , 1 2 , 1 3 , 1 4 , 1 5 , 1 6 2 2 , 2 3 , 2 4 , 2 5 , 2 6 3 3 , 3 4 , 3 5 , 3 6 4 4 , 4 5 , 4 6 5 5 , 5 6 6 6
If a 6 sided number cube is rolled twice how many possible outcomes are there?
6*6=36 1&1; 1&2; 1&3; 1&4; 1&5; 1&6 2&1; 2&2; 2&3; 2&4; 2&5; 2&6 3&1; 3&2; 3&3; 3&4; 3&5; 3&6 4&1; 4&2; 4&3; 4&4; 4&5; 4&6 5&1; 5&2; 5&3; 5&4; 5&5; 5&6 6&1; 6&2; 6&3; 6&4; 6&5; 6&6 For adding up roll one and roll two, the outcomes are 1+1= 2 1+2=2+1= 3 1+3=2+2=3+1= 4 1+4=2+3=3+2=4+1= 5 1+5=2+4=3+3=4+2=5+1= 6 1+6=2+5=3+4=4+3=5+2=6+1= 7 2+6=3+5=4+4=5+3=6+2= 8 3+6=4+5=5+4=6+3= 9 4+6=5+5=6+4= 10 5+6=6+5= 11 6+6= 12 Odds of adding up to those possible outcomes. 2 = 1:36 3 = 2:36 = 1:18 4 = 3:36 = 1:12 5 = 4:36 = 1:9 6 = 5:36 7 = 6:36 = 1:6 You will total seven more times than others. 8 = 5:36 9 = 4:36 = 1:9 10= 3:36 = 1:12 11= 2:36 = 1:18 12= 1:36
Why is 7 the most likely answer If you roll 2 fair dice and add the scores?
If you roll two dice, the following reuslts are possible: 2: 1+1 3: 1+2 , 2+1 4: 1+3, 2+2, 3+1 5: 1+4, 2+3, 3+2, 4+1 6: 1+5, 2+4, 3+3, 4+2, 5+1 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1 8: 2+6, 3+5, 4+4, 5+3, 6+2 9: 3+6, 4+5, 5+4, 6+3 10: 4+6, 5+5, 6+4 11: 5+6, 6+5 12: 6+6 As you can see, the greatest number of permutations result in a total of 7. Its probability is 6/36 or 1/6.
How many outcomes are there from rolling 10 dice?
It depends on what you define as an outcome. Let me take a simpler case: just two dice.1. Outcomes of possible sums of the two dice:2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 122. Outcomes of possible sets of two dice:{1, 1}, {1, 2}, {1, 3}, {1, 4}, {1, 5}, {1, 6}, {2, 2}, {2, 3}, {2, 4}, {2, 5}, {2, 6}, {3, 3}, {3, 4}, {3, 5}, {3, 6}, {4, 4}, {4, 5}, {4, 6}, {5, 5}, {5, 6}, {6, 6}3. Outcomes of possible combinations of two dice:(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)We would need to know which you need. Assuming you want all the possible combinations of ten 6-sided dice, then it is 610, or 60,466,176.
Can 1 2 3 and 5 equal 6?
5-3=2 1=2=3 3*2=6
What is 5 and 1 3rd minus 3 and 5 6th?
5 and 1/3 is the same as 5 and 2/6 which makes the sum alot easier; 5 and 2/6 - 5/6 = 4 and 3/6 - 3 = 1 and 3/6 or 1 and 1/2 in short.
What is 8 minus 6 and 3 fifths?
8 - 6 3/5 = (7 + 1) - (6 + 3/5) = (7 - 6) + (1 - 3/5) = 1 + 2/5 = 1 2/5.
How do you subtract and rename 5 13 3 5 6?
I'm guessing that's 5 and 1/3 - 3 and 5/6 5 and 1/3 = 5 and 2/6 = 4 and 8/6 4 and 8/6 - 3 and 5/6 = 1 and 3/6 = 1 and 1/2
What is the Abracadabra form of Numerology?
1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1
