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9y-3 = 6
Arvilla Kemmer ∙
16y-9y3 = 0 y*(16-9y2) = 0 y*(4-3y)*(4+3y) = 0 So y = 0 or (4-3y) = 0 or (4+3y) = 0 ie y = 0 or y = 4/3 or y = -4/3