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16y-9y3 = 0

y*(16-9y2) = 0

y*(4-3y)*(4+3y) = 0

So y = 0 or (4-3y) = 0 or (4+3y) = 0

ie y = 0 or y = 4/3 or y = -4/3

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13y ago
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Q: How do you solve 16y-9ycubed equals 0?
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