r = 60 m/h t = 2 h D = r t = (60m/h) x (2h) = 120 mi
a rectangular pyramid has a rectangular base and two pairs of congruent triangle sides. Given the height of the pyramid as well as its length and width, the area equals (l * w) + (l * (sq. rt ((w/2)^2 + h^2)) + (w * (sq. rt ((l/2)^2 + h^2)).
The numbers are: (-14 +sq rt 190) and (-14 -sq rt 190) Check: (-14 +sq rt 190)+(-14 -sq rt 190) = -28 and (-14 +sq rt 190)*(-14 -sq rt 190) = 6
The numbers are: -2 +2*sq rt 19 and -2 -2*sq rt 19 Check: (-2 +2*sq rt 19)*(-2 -2*sq rt 19) = -72 and (-2 +2*sq rt 19)+(-2 -2*sq rt 19) = -4
The diagonal 'D' of the rectangle is the hypotenuse of a right triangle, whose legs are the rectangle's width 'W' and height 'H'. According to old Pythagoras: D2 = W2 + H2 D = sqr-root (W2 + H2) = sqr-rt(62 + 82) = sqr-rt(36 + 64) = sqr-rt(100) = 10 In a rectangle, the diagonals are equal, so their sum is 2D = 20.
the maximum speed of an dodge challenger rt is about 270 km/h
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h = 2c /( unit weight x (sq rt of ka))
146 miles per hour (235 km/h).
If the pKa is 8.3, when Ka = 10^-pKa = 5.012*10^-9. Then, [H+]= sq. rt(Ka*C0). {C0 is the intial concentration of the acid}. [H+] = sq. rt[(5.012*10^-9)(0.05M)} = 1.58*10^-5 M Then, pH = -log[H+] pH = -log (1.58*10^-5M) = 4.8
r = 60 m/h t = 2 h D = r t = (60m/h) x (2h) = 120 mi
a rectangular pyramid has a rectangular base and two pairs of congruent triangle sides. Given the height of the pyramid as well as its length and width, the area equals (l * w) + (l * (sq. rt ((w/2)^2 + h^2)) + (w * (sq. rt ((l/2)^2 + h^2)).
rt = re tweet
For a weak acid HA, Ka = [H+] [A-]/[HA] where Ka is the dissociation constant and the square brackets are the concentrations of the species shown in mol dm-3. Percentage ionization is given by PI = [H+] /[HA] x 100 Let the molarity of the final solution be M. Then we have, for the original solution,PI = [H+] /[HA] x 100 = [H+] x 100/0.2PI= 500 [H+]From the first equation, remembering that the concentrations of the two ions are equal,[H+] = sq rt(0.2 Ka)Thus , original PI = 500 x sq rt (0.2 Ka)For the final solution, PI = [new H+]/M x 100 and as before, [new H+] = sq rt (KaM)So final PI = sq rt (KaM)/M x 100= sqrt (Ka)/sqrtM x100We know this is twice the original PI sosqrt (Ka)/sqrtM x100 = 2 x 500 x sq rt (0.2 Ka)Solving this gives M = 0.05.This is a quarter of the original molarity, ( 0.05/0.2), so the final volume should be 4 times the original, i.e. 400 ml.
It depends if you mean Reverse transcription PCR (RT-PCR) or real time PCR (qPCR) - (there are misnomers often used with real time being (RT)Earliest article I could find on reverse transcription isCoupled reverse transcription-polymerase chain reaction (RT-PCR) as a sensitive and rapid method for isozyme genotyping. Gene, 1990, 93, 271-275 published by Mocharla, H., Mocharla, R., Hodes, M. E.,
RT mean "Re-tweet" It's for twitter