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r = 60 m/h t = 2 h D = r t = (60m/h) x (2h) = 120 mi
a rectangular pyramid has a rectangular base and two pairs of congruent triangle sides. Given the height of the pyramid as well as its length and width, the area equals (l * w) + (l * (sq. rt ((w/2)^2 + h^2)) + (w * (sq. rt ((l/2)^2 + h^2)).
The numbers are: (-14 +sq rt 190) and (-14 -sq rt 190) Check: (-14 +sq rt 190)+(-14 -sq rt 190) = -28 and (-14 +sq rt 190)*(-14 -sq rt 190) = 6
The numbers are: -2 +2*sq rt 19 and -2 -2*sq rt 19 Check: (-2 +2*sq rt 19)*(-2 -2*sq rt 19) = -72 and (-2 +2*sq rt 19)+(-2 -2*sq rt 19) = -4
The diagonal 'D' of the rectangle is the hypotenuse of a right triangle, whose legs are the rectangle's width 'W' and height 'H'. According to old Pythagoras: D2 = W2 + H2 D = sqr-root (W2 + H2) = sqr-rt(62 + 82) = sqr-rt(36 + 64) = sqr-rt(100) = 10 In a rectangle, the diagonals are equal, so their sum is 2D = 20.