The answer would be 3+a right.
If N is the number, then 6 + N/3 = 18 Subtracting 6 from both sides: N/3 = 12 Multiplying both sides by 3: N = 36
Let the number be n. Then 3n + 2 = -4 3n = -6 n = -3
27
N + (2/3)*N = 45 Multiply by 3: 3N + 2N = 135 ie 5N = 135 Divide by 5: N = 27
The answer would be 3+a right.
If N is the number, then 6 + N/3 = 18 Subtracting 6 from both sides: N/3 = 12 Multiplying both sides by 3: N = 36
Three electrons must be added if a neutral nitrogen is to be converted into an N-3. This is because the nitrogen needs three negative charges to be an N-3.
Let the number be n. Then 3n + 2 = -4 3n = -6 n = -3
27
N + (2/3)*N = 45 Multiply by 3: 3N + 2N = 135 ie 5N = 135 Divide by 5: N = 27
(N x 3)+2 = -43N = -6N = -2
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
Let n be the number(n + 5) * 3 = 193n + 15 = 19subtract 15 from both sides3n = 4divide both sides by 3n = 4/3 = 1 and 1/3
Let the number be n.Then 3n + 7 = 1 : 3n = 1 - 7 = -6 : n = -6/3 = -2.Answer n = -2
28
Suppose the number is n. Then 3n + 2 = 17 Subtracting 2 from both sides: 3n = 15 Dividing both sides by 3 : n = 5